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For the function f(t)=pe rt , if p=9 and r=0.09 then what is the value of f(9) to the nearest tenth
5 months ago
Q:
For the function f(t)=pe rt , if p=9 and r=0.09 then what is the value of f(9) to the nearest tenth
Accepted Solution
A:
Answer: f(9) = 20.2 .
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Explanation:
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f(9) = pe^(r*t) = 9* e^(0.09 * 9) ;
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Note: 0.09 *9 = 0.81 .
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→ f(9) = pe^(r*t) = 9* e^0.81 ) ;
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Note: e^(0.81) = 2.24790798668.
f(9) = 9 * 2.24790798668 ;
= 20.2311718801 ;
→ Round to the nearest tenth:
f(9) = 20.2 .
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