Q:

The point-slope form of the equation of the line that passes through (-5, -1) and (10,-7) isy+7=-(x-10). What is thestandard form of the equation for this line?2x-5y = -152-5y=-17 2x+6y=-152x+5v=-17​

Accepted Solution

A:
Answer:That should be 2x + 5y = 20. Step-by-step explanation:First, you have to correct this: y + 7 = -β…–(x - 10). Now, first convert to Slope-Intercept Form by moving -7 to the other side of the equivalence symbol to get y = -β…–x + 4, then finally convert to Standard Form by moving β…–x to the other side of the equivalence symbol to end up with β…–x + y = 4.. Now, there is an extended step when it comes to fractional coefficients, and that is multiplying the whole equation by the denominator to get rid of the denominator being there in the first place, REALLY ending with 2x + 5y = 20.BUT, if your assignment says otherwise, then the first looks correct. I hope this helps.