The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds. the probability of a player weighing less than 250 pounds is closest to:
Accepted Solution
A:
Given: μ = 200 lb, the mean σ = 25, the standard deviation
For the random variable x = 250 lb, the z-score is z = (x-μ)/σ =(250 - 200)/25 = 2
From standard tables for the normal distribution, obtain P(x < 250) = 0.977