Answer:[tex]23\frac{3}{20}[/tex]Step-by-step explanation:Given: The given expression is [tex]7\frac{3}{5} +6\frac{1}{4}+9\frac{3}{10}[/tex]First, we need to convert this mixed fraction into improper fraction.Then, [tex]7\frac{3}{5} +6\frac{1}{4}+9\frac{3}{10}=\frac{38}{5} +\frac{25}{4}+\frac{93}{10}[/tex].Now we find the LCD of all the denominators.Therefore, LCD of 5,4 and 10 is 20.Now we make all denominators is equal to 20.Therefore, we multiply 5 by 4 to get 20.Now we multiply numerator 38 by 4 we get 152.Therefore, the first fraction is [tex]\frac{152}{20}[/tex] Therefore, we multiply 4 by 5 to get 20.Now we multiply numerator 25 by 5 we get 125.Therefore, the second fraction is [tex]\frac{125}{20}[/tex]Therefore, we multiply 10 by 2 to get 20.Now, we multiply numerator 93 by 2 we get 186.Therefore, the third fraction is [tex]\frac{186}{20}[/tex].Therefore, sum of all the three fractions is given as : [tex]\frac{152}{20}+\frac{125}{20}+\frac{186}{20} =\frac{152+125+186}{20} = \frac{463}{20} =23\frac{3}{20}[/tex].