For the function f(t)=pe rt , if p=9 and r=0.09 then what is the value of f(9) to the nearest tenth

Answer:   f(9) = 20.2  .
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Explanation:
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f(9) = pe^(r*t) = 9* e^(0.09 * 9) ;
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Note:  0.09 *9 = 0.81 .
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→ f(9) = pe^(r*t) = 9* e^0.81 ) ;
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Note:  e^(0.81) =  2.24790798668.

f(9) = 9 * 2.24790798668 ;

      = 20.2311718801 ;

→ Round to the nearest tenth:

f(9) = 20.2  .
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