Deangelo has $7 worth of dimes and quarters in a jar. He has 7 more quarters than dimes. How many of each coin does he have? Enter your answers in the boxes. _dimes and _ quarters
Accepted Solution
A:
0.10d + 0.25q = 7 q = d + 7
0.10d + 0.25(d + 7) = 7 0.10d + 0.25d + 1.75 = 7 0.35d = 7 - 1.75 0.35d = 5.25 d = 5.25 / 0.35 d = 15 <=== there are 15 dimes
q = d + 7 q = 15 + 7 q = 22 <== there are 22 quarters