What is the solution to the system of equations? 3x + 10y = -47 5x- 7y = 40Please and thank u

Answer:x=1, y=-5Step-by-step explanation:Given equations are:[tex]3x+10y=-47\ Eqn\ 1\\and\\5x-7y=40\ Eqn\ 2[/tex]In order to solve the equationMultiplying Eqn 1 by 5 and eqn 2 by 3 and subtracting themSo,Eqn 1 becomes15x+50y=-235Eqn 2 becomes 15x-21y=120Subtracting 2 from a15x+50y - (15x-21y) = -235-12015x+50y-15x + 21y = -35571y = -355y = -355/71y =-5Putting y= -5 in eqn 13x+10(-5) = -473x -50 = -473x = -47+503x = 3x = 3/3x = 1Hence the solution is:x=1, y=-5